幾何與角

數學 · 共 264 題 · 點擊選項即時核對答案

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51.

In the figure, ABCDABCD is a square. If CEFCEF is an equilateral triangle, then ∠CBF=\angle CBF=

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52.

In the figure, x=x=

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53.

In the figure, OABCOABC and OFEDOFED are straight lines. If AB:BC=2:3AB:BC=2:3 and FA:DC=1:5FA:DC=1:5, then OA:AB=OA:AB=

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54.

In the figure, ACEACE and BDFBDF are straight lines. If the areas of the quadrilaterals ABDCABDC and CDFECDFE are 16 cm216\text{ cm}^2 and 5 cm25\text{ cm}^2 respectively, then the length of ABAB is

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55.

In the figure, ABAB and ACAC are tangents to the circle at XX and YY respectively. ZZ is a point lying on the circle. If ∠BAC=100∘\angle BAC=100^\circ, then ∠XZY=\angle XZY=

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56.

In the figure, OO is the centre of the circle and AOCAOC is a straight line. If ABAB and BCBC are tangents to the circle such that AB=3AB=3 and BC=4BC=4, then the radius of the circle is

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57.

In the figure, ABCDABCD is a circle. If AB^:BC^:CD^:DA^=1:2:3:3\widehat{AB}:\widehat{BC}:\widehat{CD}:\widehat{DA}=1:2:3:3 and EE is a point lying on BDBD, then ∠CAE=\angle CAE=

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58.

In the figure, ABCDABCD is a parallelogram. EE, FF and GG are points lying on BCBC, CDCD and DADA respectively. AEAE and AFAF divide ∠BAD\angle BAD into three equal parts and BGBG bisects ∠ABC\angle ABC. If AEAE and AFAF intersect BGBG at HH and II respectively, then ∠GIF+∠GHE=\angle GIF+\angle GHE=

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59.

In the figure, ABCDABCD is a parallelogram and EE is a point on ADAD such that AE:ED=1:3AE:ED=1:3. If the area of △ABE\triangle ABE is 3 cm23\text{ cm}^2, then the area of the shaded region is

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60.

In the figure, ADAD and BCBC meet at EE. If CE:EB=3:1CE:EB=3:1, then area of △ABD\triangle ABD : area of △CDE=\triangle CDE=

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數學 幾何與角 DSE、CE 選擇題(第 6 頁) | dselib